Chapter 6 Solution Ops Management Essay

Chapter 6 Solution Ops Management Essay Chapter 6 Solution Ops Management Essay CHAPTER 6 PROCESS DESIGN AND Facility LAYOUT Answers to Problems 1. Longest task = 2.4 minutes Total task times = 18 minutes OT = 450 minutes per day a. Minimum cycle time = length of longest task, which is 2.4 minutes. a. Maximum cycle time = ï â€œ task times = 18 minutes.CT = 450 / 180 = 2.50 minutes per unit N = 18 / 2.5 = 7.2, round to 8 b.b. CT = 450 / 125 = 3.6 minutes per unit Range of output: e. c i. output = 450 / 9 = 50 units per day ii. output = 450 / 15 = 30 units per day 2. Desired output = 33.33 units per hour Operating time = 60 minutes per hour CT = Operating time = 60 minutes per hr. = 1.80 82 minutes per unit Desired output 33.33 units per hr. a. Station Time left Eligible Will fit Assign (time) Idle 1 1.82 0.42 a b a a (1.4) 0.42 2 1.82 1.32 0.52 b c, d, e c, d b c, d, e b (0.5) e* (0.8) 0.52 3 1.82 1.12 0.52 .02 c, d c, g g, f g c, d c, g f d* (0.7) c** (0.6) f (0.5) .02 4 1.82 0.82 0.32 g h g h g (1.0) h (0.5) 0.32 1.28 * is tied in no. of followers, but is longer(longest) ** has more followers b. Efficiency = 1 – [1.28 / 4(1.82)] = .82 or 82%. 3. Desired output = 4 units per hour Operating time = 56 minutes per hour CT = Operating time = 56 minutes per hr. = 14 minutes per unit Desired output 4 units per hr. a. Station Time left Eligible Will fit Assign (time) Idle 1 14 9 6 a, d, f a, d, g b, d, g a, d, f a, d, g b, g f* (5) a** (3) g* (6) 0 2 14 7 5 1 b, d b, e c, e c b, d b, e c, e d* (7) b** (2) e*** (4) 1 3 14 10 1 c h i c h c (4) h (9) 1 4 14 9 i i i (5) 9 11 * is tied for no. of followers, but is longer (longest) ** has more (most) no. of followers *** tied in no. of followers and time; choose randomly b. Efficiency = 1 – Total idle time = 1 – 11 = 80.4% CT x no. of stations 14(4) 1. CT = 1.3 minutes per unit Time [no. followers] .3 [3] a. i .2 [4] .4 [3] 1.3 [2] 1.2 [0] .1[3] .8[2] .3[1] a. ii Station Time left Eligible Will fit Assign (time) Idle time 1 1.3 a, c, e a, c, e a* (.2) 1.1 b, c, e b, c, e b** (.4) .7 c, e c, e c** (.3) .4 d, e e e (.1) .3 d, f 0.3 2 1.3 d, f d, f d** (1.3) 0.0 f 0.0 3 1.3 f f f (.8) .5 g g g (.3) .2 h 0.2 4 1.3 h h h (1.2) 0.1 0.1 0.6 * most followers ** tied in no. of followers, but longer (longest) a. iii Percentage idle time: ï â€œ(idle time) = .6 = 11.5% N Ãâ€" CT 4(1.3) a. iv Output: OT = 420 min./day = 323.1 units/day CT 1.3 min./unit b. i. Total time = 4.6 min., CT = Total time = 4.6 = 2.3 minutes. N 2 Assign a, b, c, d, and e to workstation 1: 2.3 minutes Assign f, g, and h to workstation 2: 2.3 minutes ii. Percentage idle time = 0 iii. Output = OT = 420 = 182.6 units per day. CT 2.3 5. Output rate = 240 units per eight-hour day a. b. CT = OT = 480 min/day = 2 minutes per unit output 240 units/day c. N = ï â€œt = 4.6 = 2.3 (round up to 3) workstations CT 2.0 d. Station Time Left Eligible Will Fit Assign (time) Idle time 1 2 a, c, e a, c, e a* (.2) 1.8 b, c, e b, c, e e** (1.2) .6 b, c, f b, c b** (.4) .2 c, f c c (.2) 0 .0 2 2 d, f d, f f** (1.2)